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How did Cleveland rank among the 2018 Best Foodie Cities in America? You might be surprised

WalletHub compared more than 180 U.S. cities across 29 key indicators of foodie-friendliness.
Credit: Getty Images

One of the aspects of Cleveland and Northeast Ohio that gives us pride is our food!

There are no shortage of terrific restaurants in our city and that excellence has been noted nationally by everyone from The Los Angeles Times, who hailed Cleveland as a “hot new dining city,” to TIME, who ranked us the seventh best food city in the country a few years ago.

That's why a recent study from Wallet Hub caught our attention.

To find the best and cheapest foodie scenes, WalletHub compared more than 180 U.S. cities across 29 key indicators of foodie-friendliness. The analytics used ranges from cost of groceries, to affordability and accessibility of high-quality restaurants, to food festivals per capita.

Cleveland checked in at #37 in the study, ranking 39th in affordability and 41st in 'diversity, accessibility, and quality.'

Source: WalletHub

Here were the Top 10 Best Foodie Cities in America:

  1. Portland, OR
  2. San Francisco, CA
  3. Miami, FL
  4. New York, NY
  5. Los Angeles, CA
  6. Orlando, FL
  7. Las Vegas, NV
  8. Seattle, WA
  9. San Diego, CA
  10. Austin, TX

As far as Ohio broke down, Cincinnati finished highest at #22, followed by Cleveland at #37, Columbus at #40, Akron at #121, and Toledo at #153.