CLEVELAND — Cleveland Indians minor-league first baseman Bobby Bradley is off to a strong start to the 2019 season, and the baseball world is taking notice.

Bradley, the Indians’ No. 6 ranked prospect, was named to the MLB Pipeline’s Prospect Team of the Week after hitting .500 with five extra-base hits and seven runs batted in over five games with Cleveland’s Triple-A affiliate, the Columbus Clippers.

Bradley collected nine hits in 18 at-bats with four runs scored, two doubles, three home runs, the seven RBI and two walks against five strikeouts over those five games last week. Bradley had splits of .500 batting average, .550 on-base percentage and 1.111 slugging percentage.

The 6-foot-1, 225-pound Bradley was a third-round pick of the Indians in the 2014 MLB First-Year Player Draft out of Harrison Central High School in Gulfport, Mississippi, and he has hit for power and driven in runs at each of his stops along the way.

In 572 career games in the Indians’ minor-league farm system, Bradley has collected 540 hits in 2,120 at-bats with 114 doubles, 17 triples and 121 home runs to go along with 325 runs scored, 437 RBI, 269 walks drawn and a .255 batting average with .343/.496/.839 splits of on-base, slugging and on-base-plus-slugging percentages.

Additionally, Bradley has been among the top 10 in the Indians’ entire farm system in home runs and RBI and was an Arizona Fall League Triple Crown winner in 2014 after leading all players in batting average, home runs and RBI.

In 32 games with the Clippers this season, his first full-time year at Triple-A, Bradley has registered 37 hits in 121 at-bats with 12 doubles, seven home runs, 21 RBI and 16 runs scored with 10 walks drawn. Bradley is hitting .306 with a split of .368 (on-base), .579 (slugging) and .947 (on-base-plus-slugging percentage).